정올문제풀이
1338 : 문자삼각형1
파아란기쁨1
2021. 11. 27. 11:18
반응형
n = int(input())
arr = [[0 for i in range(n+1)] for j in range(n+1)]
alph=ord('A')
y=0
x=n-1
for i in range(n,0,-1):
for j in range(i):
arr[y+j][x-j]=alph
alph+=1
if alph > ord('Z'):
alph = ord('A')
y+=1
for i in range(n):
for j in range(n):
if arr[i][j]==0:
print(' ',end=' ')
else:
print(chr(arr[i][j]),end=' ')
print()반응형